Errors on partition functions with NULL boundaries
breno
Posts: 4
I ran into an issue with SQL Compare, both versions 11.4.4 and 11.4.3 where comparing databases fails when there is a NULL boundary value for a partition function in the database.
For example:
create partition function test_pf (int) as range LEFT for values((NULL))
For example:
create partition function test_pf (int) as range LEFT for values((NULL))
Comments
I am assuming that the issue is similar to your latest post.
I have logged a support ticket and will email you shortly!
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