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Fails comparing a partition function with a null boundary

brenobreno Posts: 4
edited February 8, 2016 5:26AM in SQL Compare 11
I'm seeing an error where SQL Compare can't compare a database with a partition function with a null boundary.

It's pretty easy to reliably reproduce:

1)run this against a database
create partition function test_pf (date) as range LEFT for values(cast(NULL as date))

2) try to compare with another database

You get the error:

Value cannot be null.
Parameter name: value


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